In the combustion reaction of methane gas : CH4 (g) + O2 (g) --> CO2 (g) + 2 H2O (g)
4.0 X 10 exp 23 molecules of CH4 was used. Determine
(a) the moles of CO2 produced
(b) using your answer in (a), calculate the volume of CO2 produced at STP
(c) the volume of oxygen used in the reaction at STP
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Ответ:
(4.50)(x)=(0.75)(250)
(4.50)(x)=187.5
x=41.67 mL
You might want to double check the formula used, but as a chem student I’m confident this is right