Juancr4539
13.01.2021 •
Chemistry
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Ответ:
Ответ:
P = 487 Torr
mN₂ = 0.347 g
mO₂ = 0.174 g
mHe = 0.0333 g
Explanation:
Step 1: Calculate the total pressure of the mixture
The total pressure of the mixture (P) is equal to the sum of the partial pressures of the gases.
P = pN₂ + pO₂ + pHe
P = 231 Torr + 101 Torr + 155 Torr = 487 Torr
Step 2: Calculate the moles of each gas
We have 3 gases in a 1.00 L container at 25.0 °C (298.2 K). We can calculate the number of moles using the ideal gas equation: P × V = n × R × T.
nN₂ = pN₂ × V / R × T
nN₂ = 231 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.0124 mol
nO₂ = pO₂ × V / R × T
nO₂ = 101 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.00543 mol
nHe = pHe × V / R × T
nHe = 155 Torr × 1.00 L / (62.4 Torr.L/mol.K) × 298.2 K = 0.00833 mol
Step 3: Calculate the mass of each gas
The molar mass of N₂ is 28.01 g/mol.
mN₂ = 0.0124 mol × 28.01 g/mol = 0.347 g
The molar mass of O₂ is 32.00 g/mol.
mO₂ = 0.00543 mol × 32.00 g/mol = 0.174 g
The molar mass of He is 4.00 g/mol.
mHe = 0.00833 mol × 4.00 g/mol = 0.0333 g