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jayden6467
17.06.2021 •
Chemistry
It takes 45.0 J to raise the temperature of an 8.10 g piece of unknown metal from 13.0∘C to 24.3 ∘C. What is the specific heat for the metal?
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Ответ:
0.492 J/g °C
General Formulas and Concepts:
Thermodynamics
Specific Heat Formula: q = mcΔT
q is heat (in J0m is mass (in g)c is specific heat (in J/g °C)ΔT is change in temperature (in °C)Explanation:
Step 1: Define
Identify variables
[Given] q = 45.0 J
[Given] m = 8.10 g
[Given] ΔT = 24.3 °C - 13.0 °C = 11.3 °C
[Solve] c
Step 2: Solve for c
Substitute in variables [Specific Heat Formula]: 45.0 J = (8.10 g)c(11.3 °C)Multiply: 45.0 J = (91.53 g °C)cIsolate c: 0.491642 J/g °C = cRewrite: c = 0.491642 J/g °CStep 3: Check
Follow sig fig rules and round. We are given 3 sig figs.
0.491642 J/g °C ≈ 0.492 J/g °C
Ответ: