LKD Co. has 13 percent coupon bonds with a YTM of 9.7 percent. The current yield on these bonds is 10.2 percent. How many years do these bonds have left until they mature

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Ответ:

saucyboyFredo

16.02.2020

Chemistry

There are $1.1542\times 10^{25}$ molecules of water are in 345 grams.

Explanation:

$n=\frac{m}{M}$

$N=n\times N_A$

Where:

m = mass of compound

M = Molar mass of compound

N = Number of particles / atoms/ molecules

n = Number of moles

$N_A=6.022\times 10^{23} mol^{-1}$ = Avogadro's number

Mass of water = m = 345 g

Molar mas of water = M = 18 g/mol

$n=\frac{345 g}{18 g/mol}=19.167 mol$

Number of molecules of water = N

$N=19.167 mol\times 6.022\times 10^{23}mol^{-1}$

$N = 1.1542\times 10^{25} molecules$

There are $1.1542\times 10^{25}$ molecules of water are in 345 grams.

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