Mg + 2HCl MgCl2 + H2
A. If 4.9 g of Mg react with 7.8 g of HCl to produce MgCl2, which is the limiting reagent?
B. If 4.8 g of MgCl2 is produced, what is the percent yield?
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Ответ:
Explanation:
data
4.9g of Mg + 7.8g of Hcl — 4.8g of Mgcl
percentage of Mgcl = gram/ molar mass of Mgcl
Rmm of Mgcl = 24 + 81 = 105
4.8g/105*100 = 4.57%
Ответ: