Part complete how much water would you add to 175 ml of 6.00 m hydrochloric acid to prepare a 2.00 m solution of this acid?

Molarity (M) = moles of solute (mol) / Volume of the solution (L)

Molarity of the given solution = 6.00 M
Volume taken to prepare 2.00 M = 175 mL
moles in 175 mL = 6.00 M x 0.175 L
                             = 1.05 mol
Hence, moles of HCl in 2.00 M solution = 1.05 mol
By applying formula,
2.00 M = 1.05 mol / Volume
Volume = 0.525 L

Hence, volume needed to prepare the solution = 0.525 L
Volume of  6.00 M solution + volume of water   = 0.525 L

Hence, the volume of water needed to add = 0.525 L - 0.175 mL
                                                                         = 0.350 L = 350 mL

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.