Please help me double-check my Calculate the molarity of an aqueous solution that contains 36.5g KMnO4 and has a total volume of 375 mL.
My answer is 0.616M but this option is not offered.
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Ответ:
The answer to your question is Molarity = 0.6158, I got the same answer as you.
Explanation:
Data
Molarity = ?
Mass of KMnO₄ = 36.5 g
Total volume = 375 ml
Process
1.- Calculate the Molar mass of KMnO₄
KMnO₄ = (1 x 39.10) + (54.94 x 1) + (16 x 4)
= 39.10 + 54.94 + 64
= 158.04 g
2.- Calculate the moles of KMnO₄
158.04 g of KMnO₄ 1 mol
36.5 g of KMnO₄ x
x = (36.5 x 1) / 158.04
x = 0.231 mol
3.- Convert the volume to liters
1000 ml 1 L
375 ml x
x = (375 x 1)/1000
x = 0.375 L
4.- Calculate the Molarity
Molarity = moles / volume
-Substitution
Molarity = 0.231 moles / 0.375 L
Result
Molarity = 0.6158
Ответ:
Molarity = 0.616 M
Explanation:
Step 1: Data given
Mass of KMnO4 = 36.5 grams
Molar mass of KMnO4 = 158.03 g/mol
Volume of the solution = 375 mL = 0.375 L
Step 2: Calculate moles KMNO4
Moles KMnO4 = mass KMnO4 / molar mass KMnO4
Moles KMnO4 = 36.5 grams / 158.03 g/mol
Moles KMnO4 = 0.231 moles
Step 3: Calculate molarity of the aqueous solution
Molarity = moles / volume
Molarity = 0.231 moles / 0.375 L
Molarity = 0.616 M
The molarity is 0.616 M, your answer is correct. It must be an error in the options given.
Ответ: