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2KCIO3 → 2KCI + 302
How many grams of potassium chloride are produced if 52 g of potassium chlorate decompose?
A )32 g KCI
B )19 g KCI
C)44 g KCI
D)1.5 g KCI
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Ответ:
Mass of KCl : 32 g
Further explanationGiven
Reaction
2KCIO₃ → 2KCI + 30₂
52 g Potassium chlorate
Required
Mass of KCl
Solution
mol of KCIO₃ :
= mass : MW
= 52 g : 122.55 g/mol
= 0.424
From equation, mol KCl :
= 2/2 x mol KCIO₃
= 2/2 x 0.424
= 0.424
Mass KCl :
= mol x MW
= 0.424 x 74.5513 g/mol
= 31.6≈32 g
Ответ:
Explanation:
C. The author presents rational and logical reasons to support his argument