Chemistry: Que masa de metano y oxigeno se necesitan para obtener 60gr de dioxido de carbono?

The p orbitals at the second energy level are called 2px, 2py and 2pz. There are similar orbitals at subsequent levels: 3px, 3py, 3pz, 4px, 4py, 4pz and so on. All levels except for the first level have p orbitalsExplanation:...

Que masa de metano y oxigeno se necesitan para obtener

Ответ:

logan541972

01.07.2020

Chemistry

$\large \boxed{\text{22 g methane; 60 g oxygen}}$

Explanation:

1. Gather the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 16.04 32.00 44.01

CH₄ + 2O₂ ⟶ CO₂ + 2H₂O

m/g: 60

1. Moles of CO₂

$\text{Moles of CO}_{2} = \text{60 g CO}_{2} \times \dfrac{\text{1 mol CO}_{2}}{\text{44.01 g CO}_{2}} = \text{1.36 mol CO}_{2}$

2. Mass of CH₄

(a) Moles of CH₄

$\text{Moles of CH}_{4} = \text{1.36 mol CO}_{2} \times \dfrac{\text{1 mol CH}_{4}}{\text{1 mol CO}_{2}} = \text{1.36 mol CH}_{4}$

(b) Mass of CH₄

$\text{Mass of CH}_{4} = \text{1.36 mol CH}_{4} \times \dfrac{\text{16.04 g CH}_{4}}{\text{1 mol CH}_{4}} = \textbf{22 g CH}_{4}\\\\\text{The mass of CH$_{4}$ required is $\large \boxed{\textbf{22 g}}$}$

3. Mass of O₂ required

(a) Moles of O₂

$\text{Moles of O}_{2} = \text{1.36 mol CO}_{2} \times \dfrac{\text{2 mol O}_{2}}{\text{1 mol CO}_{2}} = \text{2.73 mol O}_{2}$

(b) Mass of O₂

$\text{Mass of O}_{2} = \text{2.73 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{60 g O}_{2}\\\\\text{The mass of O$_{2}$ required is $\large \boxed{\textbf{60 g}}$}$

0,0(0 оценок)

Que masa de metano y oxigeno se necesitan para obtener 60gr de dioxido de carbono?

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Chemistry

Ask an AI advisor a question