Salt water contains n sodium ions (NA ) per cubic meter and n chloride ions (Cl-) per cubic meter. A battery is connected to metal rods that dip into a narrow pipe full of salt water. The cross-sectional area of the pipe is A:

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Salt water contains n sodium ions (Na+) per cubic meter and n chloride ions (Cl−) per cubic meter. A battery is connected to metal rods that dip into a narrow pipe full of salt water. The cross sectional area of the pipe is A. The magnitude of the drift velocity of the sodium ions is VNa​ and the magnitude of the drift velocity of the chloride ions is VCl​.

What is the magnitude of the ammeter reading ?

answer :

| I | = neAVₙₐ  + neAV (Cl-)

Explanation:

Given that there are N sodium ions

Determine the Magnitude of the ammeter reading

| I | = current due to sodium ions + current due to (Cl-) ions

     = neAVₙₐ  + neAV (Cl-)

See explanation

Explanation:

The balanced equation for the formation of sulphuric acid is;

2SO2 + O2 + 2H2O → 2H2SO4

If 1 mole of SO2 occupies 22.4 L

x moles occupy 67.2 L

x = 1 × 67.2/22.4

x= 3 moles

From the reaction equation;

2 moles of SO2 yields 2 moles of H2SO4

Hence 3 moles of SO2 also yields 3 moles of H2SO4

Theoretical yield of H2SO4 = 3 moles × 98 g/mol = 294 g

Percent yield = actual yield/theoretical yield × 100

Percent yield = 250g/294g × 100

Percent yield = 85%