Chemistry: Sample a is a brand of supplement that contains iron in the form of 324mg ferrous gluconate c12h24feo14 per tablet. what is the amount of elemental iron in one table of sample a?

you have to add 1.00794 + 18.9984032 and the answer will be 20.00663432....

Sample a is a brand of supplement that contains

lbelle

31.12.2021

Amount of elemental iron in sample A is 0.0405g.

Explanation:

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of Fe = 56 g/mol

Molar mass of O = 16 g/mol

So, molar mass of ferrous gluconate = $(12\times 12)g+(24\times 1)g+(1\times 56)g+(14\times 16)g=448g$

So number of mole of ferrous gluconate in 324 mg = $\frac{0.324}{448}moles$

(number of moles = $\frac{mass}{molar mass}$ )

As 1 mol of ferrous gluconate contains 1 mol of Fe therefore $\frac{0.324}{448}moles$ of ferrous gluconate contain $\frac{0.324}{448}moles$ of Fe.

So amount of elemental iron in sample A = $\frac{0.324}{448}\times 56g=0.0405g$

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