Select all statements which are true

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astra

13.03.2022

Chemistry

Trial 1 (20.61 mL HCl):

⇒ 0.121 M

Trial 2 (20.06 mL HCl):

⇒ 0.125 M

Trial 3 (19.67 mL HCl):

⇒ 0.122 M

the answer for the next question, Compute the average concentration (molarity) of HCl for all three trials, is 0.123 M.

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