Show how the equations listed below with dHo values can be manipulated to calculate the dHo of the following equation 2KCl (s) + H2SO4 (l)> 2HCl (g) + K2SO4 dHo =?
a. HCl (g) + KOH (s)> KCl (s) + H2O (l) dHo = -200.0 kJ
b. H2SO4 (l) + 2KOH (s) > K2SO4 (s) + 2 H2O (l) = -340.0kJ

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