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connorgking
02.03.2020 •
Chemistry
Steam reforming of methane ( ) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a flask with of methane gas and of water vapor at . She then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of carbon monoxide gas to be . Calculate the pressure equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to significant digits.
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Ответ:
Explanation:
The missing data on the question are:
. . . fills a 200. mililiter flask. . . with 4.7 atm methane gasand 2.5 atm of waterat 55.0ºCpartial pressure of cabon dioxide to be 2.3 atmSolution1. Equilibrium equation:
2. ICE (initial, change, equilibrium) table:
Partial pressures in atm
I 4.7 2.5 0 0
C -x -x +x +3x
E 4.7 - x 2.5 - x x 3x
3. Partial pressures:
The partial pressure of hdyrogen gas at equilibrium is 2.3 atm
Then:
3x = 2.3 atm x = 0.7667 atm 4.7 - x = 3.9333 atm 2.5 - x = 1.7333 atm4. Pressure equilibrium constant equation:
Round to two significant figures: 1.4 atm²
Ответ:
D) The amount of heat a substance can hold.
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity.
For example,
The specific heat capacity of oil is 1.57 j/g. K and for water is 4.18 j/g.K. So, water take a time to increase its temperature by one degree by absorbing more heat while oil will heat up faster by absorbing less amount of heat.