Chemistry: Suppose the first equation is reversed and multiplied by 1/6, the second and third equations are divided by 2, and the three adjusted equations are added. What is the net reaction?3 A + 6 B → 3 D, ΔH = -402 kJ/molE + 2 F → A, ΔH = -108.3 kJ/molC → E + 3 D, ΔH = +65.5 kJ/mol

Suppose the first equation is reversed and multiplied

Ответ:

ghst

19.01.2022

Chemistry

$\frac{1C}{2} +F ----- A+B+D$ ;ΔH = + 45.6 kJ/mol

Explanation:

From the question; suppose the first equation is reversed and multiplied by $\frac{1}{6}$ ; we have:

3D ------> 3A + 6B ; ΔH = + 402 kJ/mol

$\frac{3D}{6} -----\frac{3A}{6}+\frac{6B}{6}$ ; Δ $H = +\frac{402}{6} kJ/mol$

$\frac{1D}{2} -----\frac{1A}{2}+B$ ; Δ H = +67.0kJ/mol ----Equation 1

The second and third equations are divided by 2; so are going to have the following:

E + 2 F -------> A ;ΔH = -108.3 kJ/mol

$\frac{1E}{2} +\frac{2F}{2}------\frac{1A}{2}$ ;ΔH = $\frac{-108.3 kJ/mol}{2}$

$\frac{1E}{2}+F-----\frac{1A}{2}$ ;ΔH = -54.15 kJ/mol --- Equation 2

C -------> E + 3 D ;ΔH = +65.5 kJ/mol

$\frac{C}{2}-----\frac{E}{2}+\frac{3D}{2}$ ;ΔH = $\frac{+65.5kJ/mol}{2}$

$\frac{1C}{2} -----\frac{1E}{2}+\frac{3D}{2}$ ;ΔH = + 32.75 kJ/mol --- Equation 3

Adding these three adjusted equations; we have:

$\frac{1D}{2} -----\frac{1A}{2}+B$ ; Δ H = +67.0kJ/mol

$\frac{1E}{2}+F-----\frac{1A}{2}$ ;ΔH = -54.15 kJ/mol

$\frac{1C}{2} -----\frac{1E}{2}+\frac{3D}{2}$ ;ΔH = + 32.75 kJ/mol

$\frac{1C}{2} +F ----- A+B+D$ ;ΔH = + 45.6 kJ/mol

∴ The net reaction = $\frac{1C}{2} +F ----- A+B+D$ ;ΔH = + 45.6 kJ/mol

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Ответ:

RickandMorty420710

04.03.2023

Chemistry

Strong Surface Tension, Covalent Bonds, Denser as a Liquid, Polar.

Explanation:

Water is a polar substance with strong surface tension. It is denser as a liquid than as a solid. A water molecule consists of a hydrogen atom covalently bonded to two oxygen atoms.

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Suppose the first equation is reversed and multiplied by 1/6, the second and third equations are divided by 2, and the three adjusted equations are added. What is the net reaction?3 A + 6 B → 3 D, ΔH = -402 kJ/molE + 2 F → A, ΔH = -108.3 kJ/molC → E + 3 D, ΔH = +65.5 kJ/mol

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