The density of glycerin is 1.26 g/cm3. how many pounds/foot3 is this ? use the conversion rates of 454g/1 pound and 28,317cm3/1foot3 express your answer to the correct number of significant figures
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Ответ:
78.6 lb/ft³
Step-by-step explanation:
Let's do this in steps.
1. Convert grams to pounds
D = (1.26 g/1 cm³) × (1 lb/454 g)
= 2.775 × 10⁻³ lb/cm³
2. Convert cubic centimetres to cubic feet
D = (2.775 × 10⁻³ lb/1 cm³) × (28 317cm³/1 ft³)
= 78.6 lb/ft³
Ответ:
P = 14.1 atm
Explanation:
Given data:
Mass of methane = 64 g
pressure exerted by water vapors = ?
Volume of engine = 24.0 L
Temperature = 515 K
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O + energy
Number of moles of methane:
Number of moles = mass / molar mass
number of moles = 64 g/ 16 g/mol
Number of moles = 4 mol
Now we will compare the moles of water vapors and methane.
CH₄ : H₂O
1 : 2
4 : 2/1×4 = 8 mol
Pressure of water vapors:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
P = 8 mol × 0.0821 atm.L/mol.K× 515 K / 24.0 L
P = 338.25 atm.L/ / 24.0 L
P = 14.1 atm