The net ionic equation for formation of an aqueous solution of nii2 accompanied by evolution of co2 gas via mixing solid nico3 and aqueous hydriodic acid is

Hey there!:

The balanced reaction is as follows

NiCO3(s) + 2HI(aq) ⇌ NiI2(aq) + CO2(g) + H2O(l)

The net ionic equation shows all the ions that react or change state. In this case, the only ion that does not change state is the I⁻ ion (in both reactant and product, it is aqueous).

Therefore the net ionic equation is:

NiCO3(s) + 2H⁺(aq) ⇌ Ni²⁺(aq) + CO2(g) + H2O(l)

Hope that helps!

The net ionic equation for the given reaction is given below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions. These are the ions do not get involved in a chemical equation. It is also defined as the ions which are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of nickel carbonate and hydroiodic acid is given as:

Ionic form of the above equation follows:

As, iodide ions are present on both the sides of the reaction, thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

141kg of Cadmium

794kg of Nickel

111kg of Manganese

6.32×10³kg of lithium

Explanation:

From the question I guess the number of atomes for cadmium, nickel. Manganese and lithium are 7.55×10²⁶, 8.16×10²⁷, 1.22×10²⁷, 5.48×10²⁹ atoms respectively

1 mole of a substance contains 6.022×10²³ atoms

There are 1× 7.55×10²⁶/6.022×10²³ moles in 7.55×10²⁶ atoms of Cadmium

This is equal to 1.254×10³ moles

Also, the atomic mass of cadmium is 112.411 g/ mole i.e for 112.411 g you will have a molr of cadmium. For 1.254×10³moles, you will have 112.411×1.254×10³ grams= 140.96 ×10³ grams

1000g =1kg

153.50×10³ g = 140.96×10³/1000 kg or 141kg of Cadmium

b.

There are 1× 8.15×10²⁷/6.022×10²³ moles in 8.15×10²⁷ atoms of Nickel

This is equal to 1.353×10⁴ moles

Also, the atomic mass of nickel is 58.69 g/ mole i.e for 58.69 g you will have a mole of nickel. For 1.353×10⁴moles, you will have 58.69×1.353×10⁴ grams= 79.41 ×10⁴ grams

1000g =1kg

79.41×10⁴ g = 79.41×10⁴/1000 kg or 794kg of Nickel

c.

There are 1× 1.22×10²⁷/6.022×10²³ moles in 1.22×10²⁷atoms of Manganese

This is equal to 2.026×10³ moles

Also, the atomic mass of manganese is 54.94 g/ mole i.e for 54.94 g you will have a mole of manganese. For 2.026×10³moles, you will have 54.94×2.026×10³ grams= 11.131 ×10⁴grams

1000g =1kg

11.131×10⁴ g = 11.131×10⁴/1000 kg or 111kg of Manganese

d.

There are 1× 5.48×10²⁹/6.022×10²³ moles in 5.48 ×10²⁹ atoms of lithium

This is equal to 9.1×10⁵ moles

Also, the atomic mass of lithium is 6.941 g/ mole i.e for 6.941 g you will have a mole of lithium. For 9.1×10⁵moles, you will have 6.941×9.1×10⁵ grams=63.16×10⁵grams

1000g =1kg

63.16×10⁵ g = 63.16×10⁵/1000 kg or 6.32×10³kg of lithium