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94.74 moles of NO₂ are produced.

Explanation:

Given data:

Volume of oxygen gas = 3714 L

Temperature = 273 K

Pressure = 1 atm

Moles of NO₂ produced = ?

Solution:

Chemical equation:

4NH₃  + 7O₂   →      4NO₂ + 6H₂O

Number of moles of oxygen:

At STP one mole of any gas occupy 22.4 L volume. Thus, 3714 L gas contain,

3714 L× 1  mol / 22.4 L

165.8 mol

now we will compare the moles of oxygen and nitrogen dioxide.

                    O₂         :        NO₂

                     7           :          4

                   165.8      :        4/7×165.8 = 94.74 mol

Thus, 94.74 moles of NO₂ are produced.