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katheline1226
18.01.2021 •
Chemistry
The reaction of hydrogen sulfide(g) with oxygen(g) to form water(l) and sulfur dioxide(g) proceeds as follows: 2H2S(g) 3O2(g)2H2O(l) 2SO2(g) When 9.82 g H2S(g) reacts with sufficient O2(g), 161 kJ is evolved. Calculate the value of rH for the chemical equation given. kJ/mol
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Ответ:
The value of
is 1118 .
Explanation:
To calculate the number of moles, we use the equation:
The balanced chemical reaction is:
Given :
Energy released when 0.288 mole of
is reacted = 161 kJ
Thus Energy released when 2 moles of
is reacted = ![\frac{161}{0.288}\times 2=1118kJ](/tpl/images/1043/6028/ee19c.png)
Thus the value of
is 1118.
Ответ: