Chemistry: The specific heat of ice is 0.5 calories/gram. 60 grams of ice will require calories to raise the temperature 1c.

Model B because I just took the a test about that...

The specific heat of ice is 0.5 calories/gram. - id05607100284, damien0lozano

masonrochester7

30.01.2022

Q = 30 calories

Explanation:

We have,

The specific heat of ice is 0.5 calories/gram.

The heat require to raise the temperature is given by :

$Q=mc\Delta T$

m = 60 grams, c = 0.5 calories/gram °C, $\Delta T=1\ C$

So,

$Q=60\times 0.5\times 1\\\\Q=30\ \text{calories}$

So, 30 calories of heat is required to raise the temperature by 1 C.

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