Use the periodic table to complete these charts. Complete the following charts by counting the atoms in the compounds.



Sodium Oxide - Na2O

Type of atom:
# of atoms:

Total:


Calcium Chloride - CaCl2

Type of atom:
# of atoms:

Total:


Potassium Sulphate K2SO4

Type of atom:
# of atoms:

Total:


Aluminum Iodide - AlI3

Type of atom:
# of atoms:

Total:


NH 4C2 H3O2

Type of atom:
# of atoms:

Total:


2(NH4)2CO3

Type of atom:
# of atoms:

Total:



Pb(NO3)4

Type of atom:
# of atoms:

Total:


3(PO4)2

Type of atom:
# of atoms:

Total:


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                   Option-C (The two carbon atoms share a total of six electrons with each other) is the correct answer.

Explanation:

                     According to statement the compound explained is Acetylene. It is an unsaturated hydrocarbon and belongs to class of Alkynes containing Carbon-Carbon triple bonds.

                     The lewis structure of Acetylene is attached below. As a single covalent bond is formed by sharing of two electrons therefore, the three bonds (triple bond) between the two carbons atoms will contain six electrons in total.

                     First option is incorrect because there is no lone pair of electrons on either Carbon or hydrogen atoms.

                     Second option is incorrect because the octet of both carbon atoms is complete.

                     Fourth option is incorrect because the electronegativity difference between carbon and hydrogen atoms is 0.4 and hence, the bond is nonpolar in nature.