Chemistry: Using the bond energies below, calculate an estimate of ahrxn for the gas phase reaction: qx3 + 3h20 = q(oh)3 + 3hx do not enter units with your answer. bond be (kj/mol) q-x 240 o-h 464 q-o 359 h-x 449

Using the bond energies below, calculate an estimate

datboyjulio21

02.01.2022

The reaction enthalpy is 1080 kJ/mol

Explanation:

The given reaction is:

$QX_{3} + 3H_{2}0 \rightarrow Q(OH)_{3} + 3HX$

The reaction enthalpy is given by the difference between the number of bonds broken and the number of bonds formed.

$\Delta H_{rxn}=\sum (bonds\ broken)-\sum (bonds\ formed)$

For the given reaction:

$\Delta H_{rxn}=[3(Q-X)+6(O-H)]-[3(Q-O)+3(H-X)]$

from the given bond energies:

$\Delta H_{rxn}=[3(240)+6(464)]-[3(359)+3(449)]=1080kJ/mol$

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emcarrell

28.01.2020

(decreasing particle size) C

Explanation: That is one of the answers, if there are more I am sorry.

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