Chemistry: What is the empirical formula of a compound composed of 28.7 g of potassium ( K ) and 5.87 g of oxygen ( O )? Insert subscripts as needed.

You see the number in the 10,000 th place. The 9 in 10,000 th place is rounded down because of the 4 in the hundreds place...

What is the empirical formula of a compound composed

sha712

18.01.2022

Answer : The empirical formula for the given compound is K_2O

Explanation :

Step 1: Converting the given masses into moles.

$\text{ Moles of }K=\frac{\text{ Mass of }K}{\text{ Molar mass of }K}=\frac{28.7g}{39g/mole}=0.736moles$

$\text{ Moles of }O=\frac{\text{ Mass of }O}{\text{ Molar mass of }O}=\frac{5.87g}{16g/mole}=0.367moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.367 moles.

For Potassium = $\frac{0.736}{0.367}=2.00\approx 2$

For Oxygen = $\frac{0.367}{0.367}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of K : O = 2 : 1

Hence, the empirical formula for the given compound is K_2O

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