What is the energy of a mole of photons that have a wavelength of 745 nm? (h = 6.626 × 10⁻³⁴ J • s and c = 3.00 × 10⁸ m/s) What is the wavelength of a photon if the energy is 7.03 × 10⁻¹⁹ J? (h = 6.626 × 10⁻³⁴ J • s)
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Ответ:
The energy carried by a single photon of 535 nm light is 3.71 × 10−19 J.
The equation used to find the energy in a mole of photons is E= hc/lambda where h is Planck's constant, c is the speed of light and is the wavelength of light.
Ответ:
Option B is correct.
Step-by-step explanation:
Diagram of given scenario shown below.
Given that,
Diameter of cylinder is
.
Height of cylinder is
.
So, Radius of cylinder is![= \frac{4}{2}=2\ mm](/tpl/images/0640/2471/b623f.png)
Volume of cylinder =
{where,
,
is the radius
of cylinder and
is height of cylinder}
Substituting the values we get,
Volume of cylinder![=\pi \times (2)^{2}\times 8](/tpl/images/0640/2471/015e6.png)
Therefore, Required volume of Cylinder rounding it to the nearest tenth ≈
.
Hence, option B is correct.