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iiAyeItzAsh5244
27.11.2019 •
Chemistry
What is the entropy change for freezing 2.71 g of c2h5oh at 158.7 k? ∆h = −4600 j/mol. answer in units of j/k.
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Ответ:
-1.71 J/K
Explanation:
To solve this problem we use the formula
ΔS = n*ΔH/T
Where n is mol, ΔH is enthalpy and T is temperature.
ΔH and T are already given by the problem, so now we calculate n:
Molar Mass C₂H₅OH = 46 g/mol
2.71 g C₂H₅OH ÷ 46g/mol = 0.0589 mol
Now we calculate ΔS:
ΔS = 0.0589 mol * −4600 J/mol / 158.7 K
ΔS = -1.71 J/K
Ответ:
(of bonding) resulting from electrostatic attraction between positive and negative ions; ionic. ... 'The bond that is formed between the two ions is an ionic bond (sometimes also called an electrovalent bond), and the compound produced is an ionic compound.
Explanation: