Chemistry: What is the hybridization of the central atom in po(oh)3

What is the hybridization of the central atom in po(oh)3

JJ143899

06.01.2022

Answer : The hybridization of the central atom in PO(OH)_3 is, sp^3

Explanation :

Formula used :

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the given molecule.

The given molecule is, PO(OH)_3

$\text{Number of electrons}=\frac{1}{2}\times [5+3]=4$

The number of electron pair are 4 that means the hybridization will be sp^3 and the electronic geometry of the molecule will be tetrahedral.

Hence, the hybridization of the central atom in PO(OH)_3 is, sp^3

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