What is the order of the phases on a heating curve
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Ответ:
The answer to the question is;
The concentration of AB, which is written as [AB] after 11.9 s is 0.328 M.
Explanation:
The form of the equation for the second order integrated rate law is
y = mx +b
Where:
y = 1/A
m = k
x = t and
b = 1/A₀
Therefore for the reaction
AB(g) → A(g) + B(g)
rate = k[AB]² and k = 0.20 L/mol·s we have
Since the initial concentration of AB is [AB]₀ = 1.50 M,
t = 11.9 s
k = 0.20 L/mol·s
we have
[AB] = 0.328 M
The concentration of AB after 11.9 s is 0.328 M.