What is the percent yield of aluminum phosphate if a solution containing 33.4 g of sodium phosphate produced 19.6 g of aluminum phosphate when reacted with excess aluminum chloride in solution
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Ответ:
The percent yield of aluminium phosphate in the reaction is 78.78 %
Explanation:
To calculate the number of moles, we use the equation:
.....(1)
For sodium phosphate:Given mass of sodium phosphate = 33.4 g
Molar mass of sodium phosphate = 164 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of sodium phosphate and aluminium chloride is:
By Stoichiometry of the reaction:
1 mole of sodium phosphate produces 1 mole of aluminium phosphate
So, 0.204 moles of sodium phosphate will produce =
moles of aluminium phosphate
Now, calculating the mass of aluminium phosphate from equation 1, we get:Molar mass of aluminium phosphate = 122 g/mol
Moles of aluminium phosphate = 0.204 moles
Putting values in equation 1, we get:
![0.204mol=\frac{\text{Mass of aluminium phosphate}}{122g/mol}\\\\\text{Mass of aluminium phosphate}=(0.204mol\times 122g/mol)=24.88g](/tpl/images/0546/2665/6bd51.png)
To calculate the percentage yield of aluminium phosphate, we use the equation:Experimental yield of aluminium phosphate = 19.6 g
Theoretical yield of aluminium phosphate = 24.88 g
Putting values in above equation, we get:
Hence, the percent yield of aluminium phosphate in the reaction is 78.78 %
Ответ:
d