softballlover5
14.05.2021 •
Chemistry
What is the pH of a 0.235 M Ba(OH)2 solution?
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Ответ:
13.672
Explanation:
2 moles of OH in Ba(OH)₂
0.235 M × 2 mol OH = 0.47 M OH
pOH = -log[OH-] ; pOH = -log[0.47 M OH] ; 0.328 = pOH (consider significant figures)
14 - pOH = pH because pH + pOH = 14
14 - 0.328 = 13.672 [there are three decimal places after the OH concentration, so there should be in the answer as well - 13.672]
Ответ:
Seria el compuesto : SO₂
Explanation:
El oxigeno molecular es aquel que tiene como valencia el numero -2, en el caso del SO₂ se necesitan dos moleculas de oxigeno para que reaccione con el azufre con valencia +2 y asi equiparar los valores de valencias para que quede 0.
Es decir que el numero de valencia del azufre es +2 y el del oxigeno es -1, (por eso no es molecular)de esta manera si no multiplicamos al oxigeno por dos o no ponemos en claro que serian dos moleculas las que reaccionan el valor de la suma de las dos valencias no nos daria 0.
Entonces para poder solucionar dicho fenomeno en el espacio de abajo a la derecha se le suma un 2 al oxigeno (O₂) y asi el -1 se multiplica con el 2 dando como resultado una valencia total de -2 (para el oxigeno) que da 0 al sumarla con la +2 del azufre.