What is the ph of the solution prepared by dissolving 0.927 mol hcl in enough water to make a 150 l aqueous solution?
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Ответ:
The answer to your question is pH = 2.2
Explanation:
Data
pH = ?
moles of HCl = 0.927
volume = 150 l
Process
1.- Calculate the Molar concentration of HCl
Molarity = moles / volume (L)
Molarity = 0.927 / 150
= 0.00618
2.- Calculate the pH
pH = -log [HCl]
Substitution
pH = -log [0.00618]
Result
pH = 2.2
Ответ:
English please ? & I'd be happy to help