What mass of nitrogen gas will be required to fill a 25.0L container at STP?

The mass of nitrogen gas will be 31,3 g

Explanation:

We calculate the weight of 1 mol of N2 (nytrogen gas):

Weight  1 mol N2= 2 (weight N)= 2 x 14 g/mol = 28g/mol

The conditions STP are 1 atm of pressure and 273K of temperature. We use the formula:

PV=nRT

1 atmx 25,0L= n x0,082 l atm/K mol x 272 K

n= 1 atmx 25,0L/0,082 l atm/K mol x 272 K= 1, 12 mol

1 mol N228 g

1,12mol N2---x= (1,12mol N2 x28g)/1 mol N2= 31, 3 g

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