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GreenHerbz206
29.10.2019 •
Chemistry
What volume (in mls) of 1.50 m na2co3 solution can be prepared from 3.975 g of solid na2co3?
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Ответ:
56.25 mL
Explanation:We are given;
Molarity of Na₂CO₃ = 1.50 M
Mass of Na₂CO₃ = 3.975 g
We are required to calculate the volume of Na₂CO₃
Step by step explanation:
Step 1: Determining moles of Na₂CO₃Molar mass of Na₂CO₃ = 106 g/mol
But; moles = Mass ÷ molar mass
Therefore;
Moles of Na₂CO₃ = 3.975 g ÷ 106 g/mol
= 0.0375 moles
Step 2: Calculating the volume of Na₂CO₃Relationship between volume, moles and molarity is given by;
Molarity = Moles ÷ Volume
Thus;
Volume = moles ÷ Molarity
= 0.0375 mole × 1.5 M
= 0.05625 L
But; 1 L = 1000 mL
Therefore; Volume = 56.25 mL
Hence, the volume of Na₂CO₃ is 56.25 mL
Ответ: