When benzene (C6H6) reacts with Bromine (Br2) bromobenzene (C6H5Br) is obtained. What is the theoretical yield in this reaction when 35g of benzene reacts with 75.8g of bromine? What is the percentage yield?
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Ответ:
hai ^w^
I hope this is what you meant!
We have to calculate the number of moles of Benzene involved in the reaction,
30 g / 78 moles of benzene = 0.384 moles
For bromine it will be the same process,
65 g / 159.8 moles = 0.406 moles
By observing the reaction given above we can say that the reaction ratio of bromine and benzene is 1 : 1
We need to find the mass of bromobenzene,
which should be, 6(12) + 5 (1)+ 79.90 = 156.9 g/mol
So, the mass of bromobenzene will be 156.9 g/mol X 0.3846 mol = 60.343 g
Hence the theoretical yield will be 60.34 g
Answer B) : To calculate the actual yield we have to divide it with theoretical yield.
(56.7g / 60.343 g ) X100% = 93.96 %
Here, we can say that we got 93.96 % of actual yield.
As we know it is impossible to get 100% yield in any reaction.
hope this helps! Happy Valentines Day!
☁ foamy-cloud ☁
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