Chemistry: Which is more polar, a sulfur-bromine (s−br) bond or a selenium-chlorine (se−cl) bond?

Which is more polar, a sulfur-bromine (s−br)

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cupcakes5335

12.04.2022

This can be solved using the Combined Gas Law. The formula for that is

$\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }$

Let's go ahead and fill in our known values. Since pressure remains the same, it doesn't matter what number we use, so let's assume 1 atm on both sides. For temperature, remember to convert it to Kelvin first (K = C + 273).

$\frac{(1 atm) (0.400 L)}{(323 K)} = \frac{(1 atm) (x L)}{(573 K)}$

Go ahead and simplify both sides.

0.001238 = $\frac{(x L)}{(573 K)}$

Multiply both sides by 573.

0.7095 = x L

So, at 300° C, your gas will occupy 0.7095 L.

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Which is more polar, a sulfur-bromine (s−br) bond or a selenium-chlorine (se−cl) bond?

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