kookycookiefanx
29.07.2020 •
Chemistry
Which of the following compounds will act as a strong electrolyte in solution? 1)H2CO3 2)Na2CO3 3)C12H22O11 4)CH2O
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Ответ:
ΔH =-47.3kJ
Explanation:
You must know standard enthalpy is defined as change of enthalpy during the formation of 1 mole of the substance from its constituent elements
You can find the standard enthalpy of any reaction from the sum of another similar reactions (Hess's law) as follows:
For methylamine, CH₃NH₂ is:
C(s) + 5/2 H₂(g) + 1/2 N₂(g) → CH₃NH₂ (l)
1. C(s) + O₂(g) → CO₂(g); ΔH=-393.5 kJ
2. 2H₂O(l) → 2H₂(g) + O₂(g); ΔH=571.6 kJ
3. 1/2N₂(g) + O₂(g) → NO₂(g); ΔH=33.10kJ
4. 4CH₃NH₂(l) + 13O₂(g) → 4CO₂(g) + 4NO₂(g) + 10H₂O(l); ΔH=-4110.4 kJ
The sum of (1)+(3) produce:
C(s) + 2O₂(g) + 1/2N₂(g) → CO₂(g) + NO₂(g) ΔH=-393.5kJ + 33.10kJ = -360.4kJ
-5/4 (2):
C(s) + 13/4O₂(g) + 1/2N₂(g) + 5/2H₂(g) → CO₂(g) + NO₂(g) + 5/2 H₂O(l)
ΔH= -360.4kJ -5/4 (571.6kJ) = -1074.9kJ
And this reaction -1/4 (4):
C(s) + 5/2 H₂(g) + 1/2 N₂(g) → CH₃NH₂(l)
ΔH= -1074.9kJ -1/4(-4110.4kJ)
ΔH =-47.3kJNow, you can confirm the calculated answer!