meganm9889
25.06.2019 •
Chemistry
Which of the following has the greatest electronegativity difference between the bonded atoms? a. a strong acid made of hydrogen and a halogen, such as hcl b. carbon bonded to a group 6 a (16) nonmetal chalcogen, such as in co c. a diatomic gas, such as nitrogen (n2).d. a group 1 alkali metal bonded to iodide, such as nai.
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Ответ:
Option (d) is the correct answer.
Explanation:
Electronegativity value of hydrogen is 2.2.
Electronegativity value of chlorine is 3.16.
Electronegativity value of carbon is 2.55.
Electronegativity value of oxygen is 3.44.
Electronegativity value of nitrogen is 3.04.
Electronegativity value of sodium is 0.93.
Electronegativity value of iodine is 2.66.
Therefore, calculate the electronegativity difference between the bonded atoms as follows.
Electronegativity difference of HCl = Electronegativity value of chlorine - electronegativity value of hydrogen= 3.16 - 2.2
= 0.96
Electronegativity difference of CO = Electronegativity value of oxygen - electronegativity value of carbon= 3.44 - 2.55
= 0.89
Electronegativity difference of= 3.04 - 3.04
= 0
Electronegativity difference of NaI = Electronegativity value of iodine - electronegativity value of sodium= 2.66 - 0.93
= 1.73
So, we can see that highest electronegativity difference is 1.73 and it is shown by NaI molecule.
Thus, we can conclude that a group 1 alkali metal bonded to iodide, such as NaI has the greatest electronegativity difference between the bonded atoms.
Ответ: