brycehelmke60811
14.12.2020 •
Chemistry
Which of the four cars had the least net force applied to it when it was launched down the ramp
Solved
Show answers
More tips
- S Science and Technology Why is there no gravity on other planets?...
- F Food and Cooking Deflope: What is it and how does it work?...
- B Business and Finance How to Create a Business Plan? Your Ultimate Guide...
- F Food and Cooking Unusually Delicious Shashlik - Follow the Etiquette of Proper Preparation!...
- C Computers and Internet Make Easy Accessible Screenshots on iPad in Just a Few Minutes...
- T Travel and tourism Lost in the Catacombs: What to Do?...
- F Family and Home Protect Your Home or Apartment from Pesky Ants...
- H Health and Medicine How to Treat Styes: Causes, Symptoms, and Home Remedies...
- L Legal consultation What Documents Are Required for a Russian Passport?...
- F Family and Home How to Properly Use a Water Level?...
Answers on questions: Chemistry
- S Social Studies The right of life, liberty, and the pursuit of happiness is stated in the:...
- E Engineering Now we want a way to make our monsters fight! before two monsters can fight, we need to give two new class methods that update their stats. implement a method for win_fight...
- M Mathematics Raina brought a table for 627 the price was 35%less than the original price...
- M Mathematics One Interior angle of a triangle Is 50 . The other angle mensures are and y. Which of the following could be the and y? Select all that apply. A X – 100, y = 20 0 0 0 B. X-40,...
- E English Select all the correct answers. Which two arguments does the information in the passage support? from Some Rights of Children as Persons in School Education by Charlotte Mason...
Ответ:
The least net force applied : Car 3(12 N)
Further explanationNewton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object
∑F = m. a
Car 1 ⇒m=0.5 kg, a=36 m/s²
Car 2⇒m=0.8 kg, a=50 m/s²
Car 3⇒m=0.6, a=20 m/s²
Car 4⇒m=1, a=19~m/s²
Ответ:
40 degrees Celsius
Explanation:
Equation to use: P1/T1 = P2/T2
First: add 273 K to 20 C to get 293
Then plug the numbers into the equation: 4.50/293 = 4.78/x
Then you want to cross multiply: 4.50x = 1400.54
Then solve for x: x = 313 K
Then convert back to celsius: 313 – 273 = 40 C