Will maynez burns a 0.8-g peanut beneath 76 g of water, which increases in temperature from 22âc to 46 âc. (the specific heat capacity of water is 1.0 cal/(gââ
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Ответ:
specific heat capacity, c = 1.0 cal/g°C
mass of water = 76 g
Ti = 22°C
Tf = 46°C
change in temperature, ΔT = 24°C
We can use the formula q = mcΔT to measure the amount of energy absorbed by the water to increase in tempature:
q = (76 g)(1.0 cal/g°C)(24°C)
q = 1824 cal
Therefore, the water absorbed 1824 calories from the peanut that was burned.
Ответ:
0.01
0.000001
10,000
Explanation:
plz mark brainleist