Write the equation of the mirror line for the segment with endpoints (5, 4) and (-1, -1).

Explanation:

{\displaystyle {}^{n}x}{}^{n}x, for n = 2, 3, 4, …, showing convergence to the infinitely iterated exponential between the two dots

In mathematics, tetration (or hyper-4) is an operation based on iterated, or repeated, exponentiation. It is the next hyperoperation after exponentiation, but before pentation. The word was coined by Reuben Louis Goodstein from tetra- (four) and iteration.

Under the definition as repeated exponentiation, the notation {\displaystyle {^{n}a}}{\displaystyle {^{n}a}} means {\displaystyle {a^{a^{\cdot ^{\cdot ^{a{\displaystyle {a^{a^{\cdot ^{\cdot ^{a, where n copies of a are iterated via exponentiation, right-to-left, I.e. the application of exponentiation {\displaystyle n-1}n-1 times. n is called the "height" of the function, while a is called the "base," analogous to exponentiation. It would be read as "the nth tetration of a".

Tetration is also defined recursively as

{\displaystyle {^{n}a}:={\begin{cases}1&{\text{if }}n=0\\a^{\left(^{(n-1)}a\right)}&{\text{if }}n>0\end{cases}}}{\displaystyle {^{n}a}:={\begin{cases}1&{\text{if }}n=0\\a^{\left(^{(n-1)}a\right)}&{\text{if }}n>0\end{cases}}},

allowing for attempts to extend tetration to non-natural numbers suc

The answer to your question is: Volume = 15.2 ml

Explanation:

Data

H2SO4 4M  = ?

BaO2          = 32.7 g

                        BaO2(s)  +  H2SO4(aq)  ⟶  BaSO4(s)  +  H2O2(aq)

MW BaO2 = 137 + 32 = 169 g

MW H2SO4 = 2 + 32 + 64 = 98 g

                       169 g of BaO2  98 g of H2SO4

                        32.7 g of BaO2    x

                        x = (32.7 x 98)/ 169

                        x = 18.99 ≈ 19 g of H2SO4

Density of H2SO4 = 1.25 g/lml

Volume = mass / density

Volume = 19 g / 1.25 g/ml

Volume = 15.2 ml