You need to prepare 250. ml of a 0.300 m aqueous

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Sadaalcala1

11.01.2022

The question is incomplete, here is the complete question:

You need to prepare 250. mL of a 0.300 M aqueous solution of sucrose, $C_{12}H_{22}O_{11}$ (aq), which is used frequently in biological experiments. Based on your answer above, measure out the amount of solid sucrose in the solution.

The mass of solid sucrose present in the solution is 25.7 grams.

Explanation:

To calculate the mass of sucrose, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Molarity of solution = 0.300 M

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 250. mL

Putting values in above equation, we get:

$0.300mol/L=\frac{\text{Mass of sucrose}\times 1000}{342.3g/mol\times 250.}\\\\\text{Mass of sucrose}=\frac{0.300\times 342.3\times 250.}{1000}=25.7g$

Hence, the mass of solid sucrose present in the solution is 25.7 grams.

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You need to prepare 250. ml of a 0.300 m aqueous solution of sucrose, c12h22o11 (aq), which is used frequently in biological experiments.based on your answer above, what is the value of x?

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