Assume s is a string of lower case characters.

write a program that prints the number of times the string 'bob' occurs in s. for example, if s = 'azcbobobegghakl', then your program should print

number of times bob occurs is: 2

Here's an attempt in C:

#include <string.h>

int CountBob(const char * s)
{
   int n = 0;
   while (s = strstr(s, "bob")) {
      n++; 
      s++;
   }
   return n;
}

int main()
{
   char *s = "azcbobobegghakl";
   int n = CountBob(s);
   printf("Number of times bob occurs is: %d", n);
   getchar();
}

D. A 2-column table with 3 rows. Column 1 is labeled x with entries 2, 4, 8. Column 2 is labeled y with entries 8, 16, 32.

Step-by-step explanation:

Since y must be 4x or equal to x times 4, we just take the entries and see if when multiplied by 4, the x entries equal the y entries.

A.

0 x 4 = 0

2 x 4 = 8

3 x 4 = 12

0, 8, 12   4, 8, 12

B.

1 x 4 = 4

2 x 4 = 8

3 x 4 = 12

4, 8, 12    4, 8, 16

C.

1 x 4 = 4

4 x 4 = 16

4 x 5 = 20

4, 16, 20   4, 8, 12

D.

2 x 4 = 8

4 x 4 = 16

8 x 4 = 32

8, 16, 32 = 8, 16, 32

D is the answer

I'm always happy to help :)