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dbanks701
18.01.2021 •
Engineering
g Asbestos is a fibrous silicate mineral with remarkably high tensile strength. But is no longer used because airborne asbestos particles can cause lung cancer. Grunerite, a type of asbestos, has a tensile strength of 3.5 × 10ଶ kg mmଶ ⁄ (meaning a strand of grunerite with a 1-mmଶ cross-sectional area can hold up to 3.5 × 10ଶ kg). The tensile strength of aluminum and Steel No. 5137 are 2.4 × 10ସ lb inଶ ⁄ and 5.0 × 10ସ lb inଶ ⁄ respectively. Calculate the cross section areas in mmଶ of wires of aluminum and of Steel No. 5137 that have the same tensile strength as a fiber of grunerite with a cross-sectional area of 1.0 μmଶ
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Ответ:
Aluminum cross sectional area = 1.99 * 10^-5 mm^2
Steel cross sectional area = 9.95* 10^-6 mm^2
Explanation:
Given data:
Tensile strength of Grunerite = 3.5 * 10^2 kg/mm^2 = 3.5 * 10^-4 kg/um^2
Tensile strength of Aluminum = 2.5 × 10^4 lb/in2 = 2.5 × 10^4 * 703.07 kg/m^2
Tensile strength of Steel number 5137 = 5.0 × 10^4 lb/in2 = 5.0 × 10^4*703.07 kg/m^2
Calculating the cross sectional area of the wires of aluminum and steel No5137
first we will determine the cross sectional area of the aluminum wire ( A ) by equating tensile strength of aluminum with the tensile strength
of Grunerite
(2.5 × 10^4 * 703.07) * A = 3.5 * 10^-4 kg
Hence ; A = 1.99 * 10^-5 mm^2
Next we calculate the cross sectional area of steel
5.0 × 10^4*703.07 kg/m^2 * A" = 3.5 * 10^-4 kg
Hence ; A" = 9.95* 10^-6 mm^2
Ответ:
Check the explanation
Explanation:
1 -
public int getPlayer2Move(int round)
{
int result = 0;
//If round is divided by 3
if(round%3 == 0) {
result= 3;
}
//if round is not divided by 3 and is divided by 2
else if(round%3 != 0 && round%2 == 0) {
result = 2;
}
//if round is not divided by 3 or 2
else {
result = 1;
}
return result;
}
2-
public void playGame()
{
//Initializing player 1 coins
int player1Coins = startingCoins;
//Initializing player 2 coins
int player2Coins = startingCoins;
for ( int round = 1 ; round <= maxRounds ; round++) {
//if the player 1 or player 2 coins are less than 3
if(player1Coins < 3 || player2Coins < 3) {
break;
}
//The number of coins player 1 spends
int player1Spends = getPlayer1Move();
//The number of coins player 2 spends
int player2Spends = getPlayer2Move(round);
//Remaining coins of player 1
player1Coins -= player1Spends;
//Remaining coins of player 2
player2Coins -= player2Spends;
//If player 2 spends the same number of coins as player 2 spends
if ( player1Spends == player2Spends) {
player2Coins += 1;
continue;
}
//positive difference between the number of coins spent by the two players
int difference = Math.abs(player1Spends - player2Spends) ;
//if difference is 1
if( difference == 1) {
player2Coins += 1;
continue;
}
//If difference is 2
if(difference == 2) {
player1Coins += 2;
continue;
}
}
// At the end of the game
//If player 1 coins is equal to player two coins
if(player1Coins == player2Coins) {
System.out.println("tie game");
}
//If player 1 coins are greater than player 2 coins
else if(player1Coins > player2Coins) {
System.out.println("player 1 wins");
}
//If player 2 coins is grater than player 2 coins
else if(player1Coins < player2Coins) {
System.out.println("player 2 wins");
}
}