Engineering: Singularity is an important property of a square matrix. This is also known as degenerate. What is the value of the determinant of a singular matrix?

Explanation:∞ΔT--------(1) ΔTBy equation (1) and (2)ΔT=h.4ΔT-------(4)From equation (3) and (4)So for sphere →0...

Singularity is an important property of a square

Ответ:

gstinson98

03.02.2022

Engineering

For a Singular matrix, the determinant must be equivalent to 0.

Explanation:

A matrix is a rectangular array in which elements are arranged in rows and columns.

Each square matrix has a determinant. The determinant is a numerical idea that has a fundamental function in finding the arrangement just as investigation of direct conditions. For a Singular matrix, the determinant must be equivalent to 0.

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Ответ:

dudesenpai24

09.11.2021

Engineering

Explanation:

r_2= ∞

$q=4\pi kT_1(T_2-T_1)\\$

$q=2\pi kD.$ ΔT--------(1)

q=hA ΔT $=4\pi r_1^2(T_2_s-T_1_s)\\$

$N_u=\frac{hD}{k} = 2+\frac{0.589 R_a^\frac{1}{4} }{[1+(\frac{0.046}{p_r}\frac{9}{16} )^\frac{4}{9} } ------(3)$

By equation (1) and (2)

$2\pi kD.$ ΔT=h.4 $\pi r_1^2$ ΔT

$2kD=hD^2\\\frac{hD}{k} =2\\N_u=\frac{hD}{k}=2\\$ -------(4)

From equation (3) and (4)

So for sphere R_a →0

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Singularity is an important property of a square matrix. This is also known as degenerate. What is the value of the determinant of a singular matrix?

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