Mathematics: (04.04 LC) On a coordinate grid, point T is at (2,-4) and point Sis at (2,6). The distance (in units) between points T and Sis numbers, such as 2.) (5 points) (Input only whole

(04.04 LC) On a coordinate grid, point T is at - id040429294311, iloveporche6364

doralisaponte79851

10.02.2022

The distance 'd' between T and S:

Step-by-step explanation:

As the point 'T' is located at (2, -4)

So, the point 'T' has the coordinates (2, -4)

And the point 'S' is located at (2, 6)

So, the point 'T' has the coordinates (2, 6)

The distance 'd' between T and S can be computed using the formula:

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-2\right)^2+\left(6-\left(-4\right)\right)^2}$

$=\sqrt{\left(2-2\right)^2+\left(6+4\right)^2}$

$=\sqrt{0+10^2}$

$=\sqrt{10^2}$

d=10

Therefore, the distance 'd' between T and S:

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xXCoryxKenshinXx

31.03.2022

640π

Step-by-step explanation:

Multiply 10 by 64 [8²], then attach π to it.

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