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25.10.2019 •
Mathematics
1^2 + 4^2 + 7^2 + + (3n - 2)^2 = n(6n^2-3n-1)/2
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Ответ:
for n=1 will get
1^2 = 1(6*1^2 -3*1 -1)/2
1 = 1(6-4)/2
1 = 1(2)/2
1 = 1
suppose true for n=k and prove for k = k+1
hope this will help you
Ответ:
about 18.7
Step-by-step explanation: