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ciel8809
17.12.2019 •
Mathematics
1. a bag has 5 red marbles, 6 blue marbles and 4 black marbles. what is the probability of picking a red marble, replacing it, and then picking another red marble?
2. a bag has 5 red marbles, 6 blue marbles and 4 black marbles. what is the probability of picking a
blue marble, replacing it, and then picking a black marble?
3. a bag contains 4 white marbles, 3 black marbles, and 5 red marbles. find the probability of picking a red marble?
4. a bag contains 3 white marbles, 2 black marbles, and 5 red marbles. find the probability of picking a white marble
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Ответ:
(1)![\frac{1}{9}](/tpl/images/0422/3479/f5492.png)
(2)![\frac{8}{75}](/tpl/images/0422/3479/2e53d.png)
(3)![\frac{5}{12}](/tpl/images/0422/3479/3f78e.png)
(4)![\frac{3}{10}](/tpl/images/0422/3479/b4cd0.png)
Step-by-step explanation:
(1). A bag has 5 red marbles, 6 blue marbles and 4 black marbles.
Total marbles in a bag = 5 + 6 + 4 = 15 marbles
The probability of picking a red marble
=
= ![\frac{1}{3}](/tpl/images/0422/3479/5506e.png)
By replacing it and then picking another red marble
=
= ![\frac{1}{3}](/tpl/images/0422/3479/5506e.png)
P =
×
= ![\frac{1}{9}](/tpl/images/0422/3479/f5492.png)
(2). A bag has 5 red marbles, 6 blue marbles and 4 black marbles.
Total marbles in a bag = 5 + 6 + 4 = 15 marbles.
The probability of picking a blue marble =
=
= ![\frac{2}{5}](/tpl/images/0422/3479/c236b.png)
replacing it and then picking a black marble =
= ![\frac{4}{15}](/tpl/images/0422/3479/c4bc2.png)
P =
×
= ![\frac{8}{75}](/tpl/images/0422/3479/2e53d.png)
(3). A bag contains 4 white, 3 black and 5 red marbles.
Total marbles = 4 + 3 + 5 = 12 marbles
The probability of picking a red marble =![\frac{5}{12}](/tpl/images/0422/3479/3f78e.png)
(4). A bag contains 3 white marbles, 2 black marbles and 5 red marbles.
Total marbles = 3 + 2 + 5 = 10 marbles.
The probability of picking a white marble =![\frac{3}{10}](/tpl/images/0422/3479/b4cd0.png)
(1)![\frac{1}{9}](/tpl/images/0422/3479/f5492.png)
(2)![\frac{8}{75}](/tpl/images/0422/3479/2e53d.png)
(3)![\frac{5}{12}](/tpl/images/0422/3479/3f78e.png)
(4)![\frac{3}{10}](/tpl/images/0422/3479/b4cd0.png)
Ответ: