Mathematics: 1 Find all the real and imaginary solutions to the polynomial below. 4 (x2 – 20) (-3.x2 + 4x – 8)

If binomial (3x+2) is a factor of some polynomial, then number is this polynomial s root. Check all polynomials:A. For the polynomial B. For the polynomial C. For the polynomial D. For the polynomial correct choice is B...

1 Find all the real and imaginary solutions to the

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sherry59Sherry59

02.04.2021

Mathematics

im not sure if im suppose to simplify the expression or? but if i am the answer is - 3 x^4 + 4 x^3 + 52 x 2 - 80x + 160

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I spend time editing and getting answers so can I have a brainliest and/or a thank you please <33 :)

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Ответ:

igtguith

03.11.2021

Mathematics

If binomial (3x+2) is a factor of some polynomial, then number $x=-\dfrac{2}{3}$ is this polynomial's root. Check all polynomials:

A. For the polynomial 6x^3 + 3x^2 + 4x + 2,

$6\left(-\dfrac{2}{3}\right)^3 + 3\left(-\dfrac{2}{3}\right)^2 + 4\left(-\dfrac{2}{3}\right) + 2=-\dfrac{16}{9}+\dfrac{4}{3}-\dfrac{8}{3}+2=-\dfrac{10}{9}\neq 0.$

B. For the polynomial 12x^2 + 15x + 8x + 10,

$12\left(-\dfrac{2}{3}\right)^2 + 23\left(-\dfrac{2}{3}\right) + 10=\dfrac{16}{3}-\dfrac{46}{3}+10=0.$

C. For the polynomial 18x^3-12x^2 + 9x-6,

$18\left(-\dfrac{2}{3}\right)^3 -12\left(-\dfrac{2}{3}\right)^2 + 9\left(-\dfrac{2}{3}\right) -6=-\dfrac{16}{3}-\dfrac{16}{3}-6-6\neq 0.$

D. For the polynomial 21x^4 + 7x^3 + 6x + 2,

$21\left(-\dfrac{2}{3}\right)^4 +7\left(-\dfrac{2}{3}\right)^3 +6\left(-\dfrac{2}{3}\right) +2=\dfrac{112}{27}-\dfrac{56}{27}-4+2\neq 0.$

correct choice is B

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1 Find all the real and imaginary solutions to the polynomial below.
4
(x2 – 20) (-3.x2 + 4x – 8)

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