tigermath85
12.03.2021 •
Mathematics
10
The length of a rectangle Is 4 Inches greater than the width. The perimeter of the rectangle Is 24 Inches. What are the dimenslons of the rectangle?
O length = 6 in.; width 2 in.
O length
In.; width = 4 in
C length = 12 In.; width = 8 in.
O length = 8 In.; width = 6 In.
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Ответ:
Step-by-step explanation:
length is
10.5
inches
width is
6.5
inches
Explanation:
Let length be
l
Let width be
w
Let perimeter be
P
First, we must construct an equation for these variables:
l
=
w
+
4
P
=
34
But, Perimeter of a rectangle
=
l
+
w
+
l
+
w
=
2
l
+
2
w
So:
34
=
2
l
+
2
w
But, since
l
=
w
+
4
, we can substitute for
l
, having only the
w
variable:
34
=
2
(
w
+
4
)
+
2
w
34
=
2
w
+
8
+
2
w
34
=
4
w
+
8
Solve for
w
:
4
w
=
34
−
8
4
w
=
26
w
=
26
4
w
=
6.5
inches
Now, we can substitute
6.5
for
w
in the Perimeter Equation:
34
=
2
l
+
2
w
becomes:
34
=
2
l
+
2
⋅
6.5
34
=
2
l
+
13
Solve for
l
:
2
l
=
34
−
13
2
l
=
21
l
=
21
2
l
=
10.5
inches
Thus, length is
10.5
inches
Thus, width is
6.5
inches
Ответ:
use table B
Step-by-step explanation:
the perimeter of table A =
2×(96+42) = 2× 138 = 276 inches
the perimeter of table B =
2×3.14×45 = 282.6 inches
table B > table A