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401666
17.02.2020 •
Mathematics
11
Given that
f(x) = (4 – 6k)x² + (8 – 2k)x + 4,
where k is a negative number,
(i) explain whether the coefficient of
x? is positive or negative.
(ii) find the range of values of k for
which f(x) = 0 has no real roots.
please help ♀️♀️
Solved
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Ответ:
Step-by-step explanation:
Since, k is negative, Hence, coefficient of x will always be positive. Equating (4 – 6k)x² + (8 – 2k)x + 4=0 with ax² + bx + c =0, we find: a = (4-6k), b= (8-2k) & c = 4f(x) = 0 has no real roots.Ответ:
D. Corresponding parts of similar triangles are similar.
Hope this helps!