2. A snail weighed s ounces. One day the snail drank 5 times its weight in water and ate half its weight in food. Which equation can be used to find t, the combined weight of the water and the food, in ounces, that the snail had on this day? A t= s + 5 - 1/2
B T= s +5 + 1/2
C t= 2s + s/5
D t= 5s + s/2

Option D : t = 5s + s/2 is the correct answer.

Step-by-step explanation:

Given that:

t = Combined weight of water and food

s = weight of the snail

Water drank by snail = 5s

Food ate by snail = s/2

Combined weight = Weight of water + Food

t = 5s + s/2

Hence,

Option D : t = 5s + s/2 is the correct answer.

x=45

Step-by-step explanation:

In order to solve for x, you would need to get the variable by itself. First, we would divide 1/3 on both sides.

10 = 1/3 (x - 15)

10 / (1/3) = (x - 15)

30 = x - 15

Then we would add 15 to both sides.

45 = x

Then, we can check our work by plugging the value of x into the original equation.

10 = 1/3 (x - 15)

10 = 1/3 (30)

10=10

The correct answer is x = 45